{"id":279,"date":"2024-04-01T13:56:31","date_gmt":"2024-04-01T12:56:31","guid":{"rendered":"https:\/\/tutors4you.com\/?page_id=279"},"modified":"2024-04-01T13:56:32","modified_gmt":"2024-04-01T12:56:32","slug":"finding-median-graphically","status":"publish","type":"page","link":"https:\/\/tutors4you.com\/index.php\/finding-median-graphically\/","title":{"rendered":"Finding Median Graphically"},"content":{"rendered":"\n\n\t\t
\n\t\t\t\n\t\t\t\n\t\t\t\n \n \n \n \n \n \n \n \n \n \n
Marks<\/font><\/th>\n Conversion\n into
\n exclusive series<\/font><\/th>\n 		No. of\n students<\/font><\/th>\n Cumulative\n Frequency<\/font><\/th>\n <\/tr>\n\t\t\t<\/thead>\n\t\t\t
(x)<\/font><\/td>\n  <\/td>\n (f)<\/font><\/td>\n (C.M)<\/font><\/td>\n <\/tr>\n
410-419<\/font><\/td>\n 409.5-419.5<\/font><\/td>\n 14<\/font><\/td>\n 14<\/font><\/td>\n <\/tr>\n
420-429<\/font><\/td>\n 419.5-429.5<\/font><\/td>\n 20<\/font><\/td>\n 34<\/font><\/td>\n <\/tr>\n
430-439<\/font><\/td>\n 429.5-439.5<\/font><\/td>\n 42<\/font><\/td>\n 76<\/font><\/td>\n <\/tr>\n
440-449<\/font><\/td>\n 439.5-449.5<\/font><\/td>\n 54<\/font><\/td>\n 130<\/font><\/td>\n <\/tr>\n
450-459<\/font><\/td>\n 449.5-459.5<\/font><\/td>\n 45<\/font><\/td>\n 175<\/font><\/td>\n <\/tr>\n
460-469<\/font><\/td>\n 459.5-469.5<\/font><\/td>\n 18<\/font><\/td>\n 193<\/font><\/td>\n <\/tr>\n
470-479<\/font><\/td>\n 469.5-479.5<\/font><\/td>\n 7<\/font><\/td>\n 200<\/font><\/td>\n <\/tr>\n\t\t\t<\/tbody>\n <\/table>\n

The median value of\n a series may be determinded through the graphic\n presentation of data in the form of Ogives.This can be\n done in 2 ways.<\/font><\/p>\n

1. Presenting the\n data graphically in the form of ‘less than’ ogive or\n ‘more than’ ogive .
\n 2. Presenting the data graphically and simultaneously in\n the form of ‘less than’ and ‘more than’ ogives.The two\n ogives are drawn together.<\/font><\/p>\n

1. Less than Ogive\n approach<\/font><\/p>\n \n\t\t\n \n \n \n \n \n \n \n \n \n
Marks <\/th>\n Cumulative Frequency (C.M)<\/th>\n <\/tr>\n\t\t<\/thead>\n\t\t
Less than 419.5<\/td>\n 14<\/td>\n <\/tr>\n
Less than 429.5<\/td>\n 34<\/td>\n <\/tr>\n
Less than 439.5<\/td>\n 76<\/td>\n <\/tr>\n
Less than 449.5<\/td>\n 130<\/td>\n <\/tr>\n
Less than 459.5<\/td>\n 175<\/td>\n <\/tr>\n
Less than 469.5<\/td>\n 193<\/td>\n <\/tr>\n
Less than 479.5<\/td>\n 200<\/td>\n <\/tr>\n\t\t\t<\/tbody>\n <\/table>\n

Steps involved in\n calculating median using less than Ogive approach –
\n 1. Convert the series into a ‘less than ‘ cumulative\n frequency distribution as shown above .
\n 2. Let N be the total number of students who’s data is\n given.N will also be the cumulative frequency of the last\n interval.Find the (N\/2)th <\/sup>item(student) and\n mark it on the y-axis.In this case the (N\/2)th <\/sup>item\n (student) is 200\/2 = 100th <\/sup>student.
\n 3. Draw a perpendicular from 100 to the right to cut the\n Ogive curve at point A.
\n 4.From point A where the Ogive curve is cut, draw a\n perpendicular on the x-axis. The point at which it\n touches the x-axis will be the median value of the series\n as shown in the graph.<\/font><\/p>\n


\n <\/font><\/p>\n

More than Ogive\n approach<\/font><\/p>\n \n\t\t\n \n \n \n \n \n \n \n \n \n \n
Marks <\/th>\n Cumulative Frequency (C.M)<\/th>\n <\/tr>\n\t\t<\/thead>\n\t\t
More than 409.5<\/td>\n 200<\/td>\n <\/tr>\n
More than 419.5<\/td>\n 186<\/td>\n <\/tr>\n
More than 429.5<\/td>\n 166<\/td>\n <\/tr>\n
More than 439.5<\/td>\n 124<\/td>\n <\/tr>\n
More than 449.5<\/td>\n 70<\/td>\n <\/tr>\n
More than 459.5<\/td>\n 25<\/td>\n <\/tr>\n
More than 469.5<\/td>\n 7<\/td>\n <\/tr>\n
More than 479.5<\/td>\n 0<\/td>\n <\/tr>\n\t\t\t<\/tbody>\n <\/table>\n

Steps involved in\n calculating median using more than Ogive approach –
\n 1. Convert the series into a ‘more than ‘ cumulative\n frequency distribution as shown above .
\n 2. Let N be the total number of students who’s data is\n given.N will also be the cumulative frequency of the last\n interval.Find the (N\/2)th <\/sup>item(student) and\n mark it on the y-axis.In this case the (N\/2)th <\/sup>item\n (student) is 200\/2 = 100th <\/sup>student.
\n 3. Draw a perpendicular from 100 to the right to cut the\n Ogive curve at point A.
\n 4.From point A where the Ogive curve is cut, draw a\n perpendicular on the x-axis. The point at which it\n touches the x-axis will be the median value of the series\n as shown in the graph.<\/font><\/p>\n

<\/img><\/p>\n

2.Less than and\n more than Ogive approach<\/font><\/p>\n

Another way of\n graphical determination of median is through simultaneous\n graphic presentation of both the less than and more than\n Ogives.<\/font><\/p>\n

1.Mark the point A\n where the Ogive curves cut each other.
\n 2.Draw a perpendicular from A on the x-axis. The\n corresponding value on the x-axis would be the median\n value.<\/font><\/p>\n

<\/font><\/p>\n

ssasd<\/font><\/p>\n <\/td>\n \n\t\t<\/div>\n\t\n","protected":false},"excerpt":{"rendered":"

Marks Conversion into exclusive series No. of students Cumulative Frequency (x)   (f) (C.M) 410-419 409.5-419.5 14 14 420-429 419.5-429.5 20 34 430-439 429.5-439.5 42 76 440-449 439.5-449.5 54 130 450-459 449.5-459.5 45 175 460-469 459.5-469.5 18 193 470-479 469.5-479.5 7 200 The median value of a series may be determinded through the graphic presentation […]<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"footnotes":""},"class_list":["post-279","page","type-page","status-publish","hentry"],"blocksy_meta":[],"yoast_head":"\nFinding Median Graphically - Tutors 4 You<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/tutors4you.com\/index.php\/finding-median-graphically\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Finding Median Graphically - 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