{"id":323,"date":"2024-04-02T07:18:27","date_gmt":"2024-04-02T06:18:27","guid":{"rendered":"https:\/\/tutors4you.com\/?page_id=323"},"modified":"2024-04-02T07:18:28","modified_gmt":"2024-04-02T06:18:28","slug":"enthalpy-of-heat-content","status":"publish","type":"page","link":"https:\/\/tutors4you.com\/index.php\/enthalpy-of-heat-content\/","title":{"rendered":"Enthalpy of Heat Content"},"content":{"rendered":"\n<div class=\"well well-sm\">\n\t\t\t\n\t\t\t<p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\">Let us again consider <\/font><a\n        href=\"thermodynamicsfirstlaw.htm\"><font color=\"#000080\"\n        size=\"4\" face=\"Arial\">first law of thermodynamics<\/font><\/a><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\"><img loading=\"lazy\" decoding=\"async\" src=\"\/wp-content\/uploads\/2024\/03\/delta.jpg\" width=\"16\" height=\"17\">U\n        = Q + W<\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\">or Q = <img loading=\"lazy\" decoding=\"async\" src=\"\/wp-content\/uploads\/2024\/03\/delta.jpg\" width=\"16\"\n        height=\"17\">U &#8211; W<\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\">If Q is the heat absorbed by the system, <img loading=\"lazy\" decoding=\"async\"\n        src=\"\/wp-content\/uploads\/2024\/03\/delta.jpg\" width=\"16\" height=\"17\">U is the increase\n        in internal energy and W is the work done by the system.\n        If pressure is constant,<\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\">W = &#8211; P<img loading=\"lazy\" decoding=\"async\" src=\"\/wp-content\/uploads\/2024\/03\/delta.jpg\" width=\"16\"\n        height=\"17\">U<\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\">Q = <img loading=\"lazy\" decoding=\"async\" src=\"\/wp-content\/uploads\/2024\/03\/delta.jpg\" width=\"16\"\n        height=\"17\">U &#8211; (-P<img loading=\"lazy\" decoding=\"async\" src=\"\/wp-content\/uploads\/2024\/03\/delta.jpg\" width=\"16\"\n        height=\"17\">U) = <img loading=\"lazy\" decoding=\"async\" src=\"\/wp-content\/uploads\/2024\/03\/delta.jpg\" width=\"16\"\n        height=\"17\">U + P<img loading=\"lazy\" decoding=\"async\" src=\"\/wp-content\/uploads\/2024\/03\/delta.jpg\" width=\"16\"\n        height=\"17\">U<\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\">If internal energy increases from U<sub>1 <\/sub>to\n        U<sub>2<\/sub> and volume increases from V<sub>1<\/sub> to\n        V<sub>2<\/sub> then,<\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\"><img loading=\"lazy\" decoding=\"async\" src=\"\/wp-content\/uploads\/2024\/03\/delta.jpg\" width=\"16\" height=\"17\">U\n        = U<sub>2<\/sub> &#8211; U<sub>1<\/sub> and <img loading=\"lazy\" decoding=\"async\" src=\"\/wp-content\/uploads\/2024\/03\/delta.jpg\"\n        width=\"16\" height=\"17\">U = V<sub>2<\/sub> &#8211; V<sub>1<\/sub><\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\">Substituting we get<\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\">Q = (U<sub>2<\/sub> &#8211; U<sub>1<\/sub>) + P(V<sub>2<\/sub>\n        &#8211; V<sub>1<\/sub>)<\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\">= (U<sub>2<\/sub> + PV<sub>2<\/sub>) &#8211; (U<sub>1<\/sub>\n        + PV<sub>1<\/sub>)<\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\">U<sub>1<\/sub>, P and V are functions of\n        state, thus the quantity U + PV must also be a state\n        function.<\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\">(U + PV) is called the heat content or <\/font><font\n        color=\"#FF0000\" size=\"4\" face=\"Arial\">enthalpy <\/font><font\n        color=\"#000080\" size=\"4\" face=\"Arial\">of the system. It\n        is represented by symbol H.<\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\">H = U + PV<\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\">Now H<sub>2<\/sub> = U<sub>2<\/sub> + PV<sub>2<\/sub><\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\">and H<sub>1<\/sub> = U<sub>1<\/sub> + PV<sub>1<\/sub><\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\">Q = H<sub>2<\/sub> + H<sub>1<\/sub><\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\">Q = <img loading=\"lazy\" decoding=\"async\" src=\"\/wp-content\/uploads\/2024\/03\/delta.jpg\" width=\"16\"\n        height=\"17\">V<\/font><\/p>\n        <p align=\"left\"><font color=\"#FF0000\" size=\"4\"\n        face=\"Arial\">Enthalpy change <\/font><font color=\"#000080\"\n        size=\"4\" face=\"Arial\">of a system is equal to the heat\n        absorbed or evolved by the system at constant pressure.<\/font><\/p>\n        <p align=\"left\"><font color=\"#FF0000\" size=\"4\"\n        face=\"Arial\">Enthalpy <\/font><font color=\"#000080\"\n        size=\"4\" face=\"Arial\">of a substance or a system is the\n        energy stored within the substance or the system that is\n        available for conversion into heat.<\/font><\/p>\n        <p align=\"left\"><font color=\"#FF0000\" size=\"4\"\n        face=\"Arial\">Hess&#8217;s law of constant heat summation: <\/font><font\n        color=\"#000080\" size=\"4\" face=\"Arial\">The total amount of\n        heat evolved or absorbed in a reaction is the same\n        whether the reaction takes place in one step or in a\n        number of steps.<\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\">In other words, the total amount of heat\n        exchange in a reaction depends only upon the nature of\n        the initial reactants and the nature of the final\n        products and is independent of the path or the manner by\n        which the change is brought about.<\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\">Thus, the thermo chemical equations can be\n        treated as algebraic equations which can be added,\n        subtracted, multiplied or divided.<\/font><\/p>\n        <p align=\"left\"><font color=\"#008000\" size=\"4\"\n        face=\"Arial\">Example: calculate the enthalpy of formation\n        of carbon monoxide (CO) from the following data:<\/font><\/p>\n        <p align=\"left\"><font color=\"#008000\" size=\"4\"\n        face=\"Arial\">(i)&nbsp;&nbsp; C(s) + O<sub>2<\/sub>(g) ? CO<sub>2<\/sub>(g)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;\n        &#8212;&#8211;&nbsp;&nbsp; (1)<\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\"><img loading=\"lazy\" decoding=\"async\" src=\"\/wp-content\/uploads\/2024\/03\/delta.jpg\" width=\"16\" height=\"17\"><\/font><font\n        color=\"#008000\" size=\"4\" face=\"Arial\">H = &#8211; 393.3 kJ\/mol<\/font><\/p>\n        <p align=\"left\"><font color=\"#008000\" size=\"4\"\n        face=\"Arial\">(ii)&nbsp; CO(g) + O<sub>2<\/sub>(g) ? CO<sub>2<\/sub>(g)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;\n        &#8212;&#8211;&nbsp;&nbsp; (2)<\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\"><img loading=\"lazy\" decoding=\"async\" src=\"\/wp-content\/uploads\/2024\/03\/delta.jpg\" width=\"16\" height=\"17\"><\/font><font\n        color=\"#008000\" size=\"4\" face=\"Arial\">H = -282.8 kJ\/mol<\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\">Solution:<\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\">We have to obtain<\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\">C(s) + O<sub>2<\/sub>(g) ? CO(g)<\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\">Subtracting equation (2) from equation (1)<\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\">C(s) + O<sub>2<\/sub>(g) &#8211; CO(g) &#8211; O<sub>2<\/sub>(g)\n        &#8211; CO<sub>2<\/sub>(g)<\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\">C(s) + O<sub>2<\/sub>(g) ? CO(g)<\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\"><img loading=\"lazy\" decoding=\"async\" src=\"\/wp-content\/uploads\/2024\/03\/delta.jpg\" width=\"16\" height=\"17\">H\n        = -393.3 &#8211; (-282.8) = -110.5 kJ\/mol<\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\">Thus, heat of formation of CO is <\/font><\/p>\n        <p align=\"left\"><font color=\"#000080\" size=\"4\"\n        face=\"Arial\"><img loading=\"lazy\" decoding=\"async\" src=\"\/wp-content\/uploads\/2024\/03\/delta.jpg\" width=\"16\" height=\"17\">H<sub>f<\/sub>\n        = 110.5 kJ\/mol<\/font><\/p>\n       \t\t\n\t\t<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Let us again consider first law of thermodynamics U = Q + W or Q = U &#8211; W If Q is the heat absorbed by the system, U is the increase in internal energy and W is the work done by the system. If pressure is constant, W = &#8211; PU Q = U [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"footnotes":""},"class_list":["post-323","page","type-page","status-publish","hentry"],"blocksy_meta":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v25.9 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Enthalpy of Heat Content - Tutors 4 You<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/tutors4you.com\/index.php\/enthalpy-of-heat-content\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Enthalpy of Heat Content - Tutors 4 You\" \/>\n<meta property=\"og:description\" content=\"Let us again consider first law of thermodynamics U = Q + W or Q = U &#8211; W If Q is the heat absorbed by the system, U is the increase in internal energy and W is the work done by the system. 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